Optimal. Leaf size=295 \[ -\frac{5 b \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^4}{e^6 (a+b x) (d+e x)}+\frac{\sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^5}{2 e^6 (a+b x) (d+e x)^2}-\frac{10 b^2 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^3 \log (d+e x)}{e^6 (a+b x)}+\frac{b^5 \sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^3}{3 e^6 (a+b x)}-\frac{5 b^4 \sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^2 (b d-a e)}{2 e^6 (a+b x)}+\frac{10 b^3 x \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^2}{e^5 (a+b x)} \]
[Out]
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Rubi [A] time = 0.432678, antiderivative size = 295, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 2, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.071 \[ -\frac{5 b \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^4}{e^6 (a+b x) (d+e x)}+\frac{\sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^5}{2 e^6 (a+b x) (d+e x)^2}-\frac{10 b^2 \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^3 \log (d+e x)}{e^6 (a+b x)}+\frac{b^5 \sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^3}{3 e^6 (a+b x)}-\frac{5 b^4 \sqrt{a^2+2 a b x+b^2 x^2} (d+e x)^2 (b d-a e)}{2 e^6 (a+b x)}+\frac{10 b^3 x \sqrt{a^2+2 a b x+b^2 x^2} (b d-a e)^2}{e^5 (a+b x)} \]
Antiderivative was successfully verified.
[In] Int[(a^2 + 2*a*b*x + b^2*x^2)^(5/2)/(d + e*x)^3,x]
[Out]
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Rubi in Sympy [A] time = 38.6056, size = 231, normalized size = 0.78 \[ \frac{10 b^{2} \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{3}{2}}}{3 e^{3}} + \frac{5 b^{2} \left (3 a + 3 b x\right ) \left (a e - b d\right ) \sqrt{a^{2} + 2 a b x + b^{2} x^{2}}}{3 e^{4}} + \frac{10 b^{2} \left (a e - b d\right )^{2} \sqrt{a^{2} + 2 a b x + b^{2} x^{2}}}{e^{5}} + \frac{10 b^{2} \left (a e - b d\right )^{3} \sqrt{a^{2} + 2 a b x + b^{2} x^{2}} \log{\left (d + e x \right )}}{e^{6} \left (a + b x\right )} - \frac{5 b \left (a + b x\right ) \left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{3}{2}}}{2 e^{2} \left (d + e x\right )} - \frac{\left (a^{2} + 2 a b x + b^{2} x^{2}\right )^{\frac{5}{2}}}{2 e \left (d + e x\right )^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate((b**2*x**2+2*a*b*x+a**2)**(5/2)/(e*x+d)**3,x)
[Out]
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Mathematica [A] time = 0.220048, size = 248, normalized size = 0.84 \[ \frac{\sqrt{(a+b x)^2} \left (-3 a^5 e^5-15 a^4 b e^4 (d+2 e x)+30 a^3 b^2 d e^3 (3 d+4 e x)+30 a^2 b^3 e^2 \left (-5 d^3-4 d^2 e x+4 d e^2 x^2+2 e^3 x^3\right )+15 a b^4 e \left (7 d^4+2 d^3 e x-11 d^2 e^2 x^2-4 d e^3 x^3+e^4 x^4\right )-60 b^2 (d+e x)^2 (b d-a e)^3 \log (d+e x)+b^5 \left (-27 d^5+6 d^4 e x+63 d^3 e^2 x^2+20 d^2 e^3 x^3-5 d e^4 x^4+2 e^5 x^5\right )\right )}{6 e^6 (a+b x) (d+e x)^2} \]
Antiderivative was successfully verified.
[In] Integrate[(a^2 + 2*a*b*x + b^2*x^2)^(5/2)/(d + e*x)^3,x]
[Out]
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Maple [B] time = 0.026, size = 502, normalized size = 1.7 \[{\frac{-120\,\ln \left ( ex+d \right ) x{b}^{5}{d}^{4}e-150\,{a}^{2}{b}^{3}{d}^{3}{e}^{2}-3\,{a}^{5}{e}^{5}-27\,{b}^{5}{d}^{5}+180\,\ln \left ( ex+d \right ){x}^{2}a{b}^{4}{d}^{2}{e}^{3}-180\,\ln \left ( ex+d \right ){x}^{2}{a}^{2}{b}^{3}d{e}^{4}-60\,\ln \left ( ex+d \right ){x}^{2}{b}^{5}{d}^{3}{e}^{2}+120\,\ln \left ( ex+d \right ) x{a}^{3}{b}^{2}d{e}^{4}-360\,\ln \left ( ex+d \right ) x{a}^{2}{b}^{3}{d}^{2}{e}^{3}+360\,\ln \left ( ex+d \right ) xa{b}^{4}{d}^{3}{e}^{2}-60\,\ln \left ( ex+d \right ){b}^{5}{d}^{5}+15\,{x}^{4}a{b}^{4}{e}^{5}-5\,{x}^{4}{b}^{5}d{e}^{4}+60\,{x}^{3}{a}^{2}{b}^{3}{e}^{5}+20\,{x}^{3}{b}^{5}{d}^{2}{e}^{3}+63\,{x}^{2}{b}^{5}{d}^{3}{e}^{2}-30\,x{a}^{4}b{e}^{5}+6\,x{b}^{5}{d}^{4}e-15\,{a}^{4}bd{e}^{4}+90\,{a}^{3}{b}^{2}{d}^{2}{e}^{3}+105\,a{b}^{4}{d}^{4}e-60\,{x}^{3}a{b}^{4}d{e}^{4}+120\,{x}^{2}{a}^{2}{b}^{3}d{e}^{4}-165\,{x}^{2}a{b}^{4}{d}^{2}{e}^{3}+60\,\ln \left ( ex+d \right ){a}^{3}{b}^{2}{d}^{2}{e}^{3}-180\,\ln \left ( ex+d \right ){a}^{2}{b}^{3}{d}^{3}{e}^{2}+180\,\ln \left ( ex+d \right ) a{b}^{4}{d}^{4}e+120\,x{a}^{3}{b}^{2}d{e}^{4}-120\,x{a}^{2}{b}^{3}{d}^{2}{e}^{3}+60\,\ln \left ( ex+d \right ){x}^{2}{a}^{3}{b}^{2}{e}^{5}+2\,{x}^{5}{b}^{5}{e}^{5}+30\,xa{b}^{4}{d}^{3}{e}^{2}}{6\, \left ( bx+a \right ) ^{5}{e}^{6} \left ( ex+d \right ) ^{2}} \left ( \left ( bx+a \right ) ^{2} \right ) ^{{\frac{5}{2}}}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int((b^2*x^2+2*a*b*x+a^2)^(5/2)/(e*x+d)^3,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^(5/2)/(e*x + d)^3,x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.210661, size = 562, normalized size = 1.91 \[ \frac{2 \, b^{5} e^{5} x^{5} - 27 \, b^{5} d^{5} + 105 \, a b^{4} d^{4} e - 150 \, a^{2} b^{3} d^{3} e^{2} + 90 \, a^{3} b^{2} d^{2} e^{3} - 15 \, a^{4} b d e^{4} - 3 \, a^{5} e^{5} - 5 \,{\left (b^{5} d e^{4} - 3 \, a b^{4} e^{5}\right )} x^{4} + 20 \,{\left (b^{5} d^{2} e^{3} - 3 \, a b^{4} d e^{4} + 3 \, a^{2} b^{3} e^{5}\right )} x^{3} + 3 \,{\left (21 \, b^{5} d^{3} e^{2} - 55 \, a b^{4} d^{2} e^{3} + 40 \, a^{2} b^{3} d e^{4}\right )} x^{2} + 6 \,{\left (b^{5} d^{4} e + 5 \, a b^{4} d^{3} e^{2} - 20 \, a^{2} b^{3} d^{2} e^{3} + 20 \, a^{3} b^{2} d e^{4} - 5 \, a^{4} b e^{5}\right )} x - 60 \,{\left (b^{5} d^{5} - 3 \, a b^{4} d^{4} e + 3 \, a^{2} b^{3} d^{3} e^{2} - a^{3} b^{2} d^{2} e^{3} +{\left (b^{5} d^{3} e^{2} - 3 \, a b^{4} d^{2} e^{3} + 3 \, a^{2} b^{3} d e^{4} - a^{3} b^{2} e^{5}\right )} x^{2} + 2 \,{\left (b^{5} d^{4} e - 3 \, a b^{4} d^{3} e^{2} + 3 \, a^{2} b^{3} d^{2} e^{3} - a^{3} b^{2} d e^{4}\right )} x\right )} \log \left (e x + d\right )}{6 \,{\left (e^{8} x^{2} + 2 \, d e^{7} x + d^{2} e^{6}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^(5/2)/(e*x + d)^3,x, algorithm="fricas")
[Out]
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \[ \text{Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b**2*x**2+2*a*b*x+a**2)**(5/2)/(e*x+d)**3,x)
[Out]
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GIAC/XCAS [A] time = 0.223047, size = 508, normalized size = 1.72 \[ -10 \,{\left (b^{5} d^{3}{\rm sign}\left (b x + a\right ) - 3 \, a b^{4} d^{2} e{\rm sign}\left (b x + a\right ) + 3 \, a^{2} b^{3} d e^{2}{\rm sign}\left (b x + a\right ) - a^{3} b^{2} e^{3}{\rm sign}\left (b x + a\right )\right )} e^{\left (-6\right )}{\rm ln}\left ({\left | x e + d \right |}\right ) + \frac{1}{6} \,{\left (2 \, b^{5} x^{3} e^{6}{\rm sign}\left (b x + a\right ) - 9 \, b^{5} d x^{2} e^{5}{\rm sign}\left (b x + a\right ) + 36 \, b^{5} d^{2} x e^{4}{\rm sign}\left (b x + a\right ) + 15 \, a b^{4} x^{2} e^{6}{\rm sign}\left (b x + a\right ) - 90 \, a b^{4} d x e^{5}{\rm sign}\left (b x + a\right ) + 60 \, a^{2} b^{3} x e^{6}{\rm sign}\left (b x + a\right )\right )} e^{\left (-9\right )} - \frac{{\left (9 \, b^{5} d^{5}{\rm sign}\left (b x + a\right ) - 35 \, a b^{4} d^{4} e{\rm sign}\left (b x + a\right ) + 50 \, a^{2} b^{3} d^{3} e^{2}{\rm sign}\left (b x + a\right ) - 30 \, a^{3} b^{2} d^{2} e^{3}{\rm sign}\left (b x + a\right ) + 5 \, a^{4} b d e^{4}{\rm sign}\left (b x + a\right ) + a^{5} e^{5}{\rm sign}\left (b x + a\right ) + 10 \,{\left (b^{5} d^{4} e{\rm sign}\left (b x + a\right ) - 4 \, a b^{4} d^{3} e^{2}{\rm sign}\left (b x + a\right ) + 6 \, a^{2} b^{3} d^{2} e^{3}{\rm sign}\left (b x + a\right ) - 4 \, a^{3} b^{2} d e^{4}{\rm sign}\left (b x + a\right ) + a^{4} b e^{5}{\rm sign}\left (b x + a\right )\right )} x\right )} e^{\left (-6\right )}}{2 \,{\left (x e + d\right )}^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate((b^2*x^2 + 2*a*b*x + a^2)^(5/2)/(e*x + d)^3,x, algorithm="giac")
[Out]